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# srdanova math

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### #1 msbiljanica

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Posted 09 January 2012 - 03:11 PM

SRDANOVA MATHEMATICS
Revision of the current mathematics
Marjanovic Srdan
M.Biljanica
16201 Manojlovce
Serbia
ms.biljanica@gmail.com
Introduction: I think that the current limited maths and sinful and should be reviewed with all new
things that I discovered. I will explain the mathematical space with two starting points ( along the
natural and real ).

Natural Base:
Natural along is what you see along the fig,1.Natural along has its beginning and its end , this
property natural long we will contact points ( fig.2).Natural length along the ground ( natural
meaning).Two more natural and longer merge points
[S1]-along nature (fig. 1-a), [Sn]-mathematical facts
[S2]-point ( natural meaning , Fig.2 -A( B ))
The points will mark capital letters along the (length) small letters
Definition of - teo points A,B , the length between points AB
CM (current mathematics) - does not recognize the concept of nature along , the point is not
defined so that all l everything
__________________________________________________ ___________
Presupposition-Natural long - merge points in the direction AB
Process:
P1-AB..CD..ABC(AC)
to read: natural along AB to point B, is connected to the natural long CD to point C, shall be
renaming of points, we get along ABC (AC)
P2-ABC (AC) .. DE ..ABCD (AD)
read it: along the ABC (AC) to point C, connecting with the natural long-DE to point D is done
renaming of points, we get along ABCD(AD)
...
[S3]-along (from natural long, two or more)
Definition of the initial-and the last point, the length between the initial and final points.
CM-I do not know the connection of natural longer, not along the natural base, but the real (the line , proof)
__________________________________________________ ______________
Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0.1),
...,( 0,1,2,3,4,5,6,7,8,9 ),...
The process:
P1-N(0)= {0,00,000,0000,...}
P2-N(0,1)= {0,1,10,11,100,...}
...
P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
...
[S4]-numeric along
[S5]-set of natural numbers N
We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12 ,...}
Definition of-numeric along a starting point, the last point at infinity
-The number 0 is the point 0
-Other numbers are longer, the first item is 0, the last point is the point of the name (number)
CM-I know the term but long term numeric numeric rays (line)
Natural numbers and zeros are given axiom

### #2 Saru

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Posted 09 January 2012 - 03:25 PM

Welcome to the forums.

Can you summarise this in laymen's terms and elaborate on what it is specifically you'd like to discuss ?

### #3 and then

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Posted 10 January 2012 - 01:10 AM

Imagination is the power in the turn of a phrase.

### #4 Robbie333

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Posted 10 January 2012 - 04:58 PM

msbiljanica, on 09 January 2012 - 03:11 PM, said:

SRDANOVA MATHEMATICS
Revision of the current mathematics
a1.png
Marjanovic Srdan
M.Biljanica
16201 Manojlovce
Serbia
ms.biljanica@gmail.com
Introduction: I think that the current limited maths and sinful and should be reviewed with all new
things that I discovered. I will explain the mathematical space with two starting points ( along the
natural and real ).

Natural Base:
Natural along is what you see along the fig,1.Natural along has its beginning and its end , this
property natural long we will contact points ( fig.2).Natural length along the ground ( natural
meaning).Two more natural and longer merge points
a2.png
[S1]-along nature (fig. 1-a), [Sn]-mathematical facts
[S2]-point ( natural meaning , Fig.2 -A( B ))
The points will mark capital letters along the (length) small letters
Definition of - teo points A,B , the length between points AB
CM (current mathematics) - does not recognize the concept of nature along , the point is not
defined so that all l everything
__________________________________________________ ___________
Presupposition-Natural long - merge points in the direction AB
Process:
P1-AB..CD..ABC(AC)
to read: natural along AB to point B, is connected to the natural long CD to point C, shall be
renaming of points, we get along ABC (AC)
P2-ABC (AC) .. DE ..ABCD (AD)
read it: along the ABC (AC) to point C, connecting with the natural long-DE to point D is done
renaming of points, we get along ABCD(AD)
...
a3.png
[S3]-along (from natural long, two or more)
Definition of the initial-and the last point, the length between the initial and final points.
CM-I do not know the connection of natural longer, not along the natural base, but the real (the line , proof)
__________________________________________________ ______________
Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0.1),
...,( 0,1,2,3,4,5,6,7,8,9 ),...
The process:
P1-N(0)= {0,00,000,0000,...}
P2-N(0,1)= {0,1,10,11,100,...}
...
P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
...
a4.png
[S4]-numeric along
[S5]-set of natural numbers N
We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12 ,...}
Definition of-numeric along a starting point, the last point at infinity
-The number 0 is the point 0
-Other numbers are longer, the first item is 0, the last point is the point of the name (number)
CM-I know the term but long term numeric numeric rays (line)
Natural numbers and zeros are given axiom

You are way beyond me. I struggled in college but I have been staring at this since you put it up and it makes sense--to a point. I will need a few weeks to decipher this, at least where I can get a better grasp, LOL. Good stuff and I see your basic point but I feel like Saru. You need to clean it up for us less fortunate math pupils to clarify your point, LOL. Fun stuff, thank you.

Robbie James

### #5 Cryptozological Mascot

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Posted 10 January 2012 - 10:40 PM

Geez guys... you don't get this?  Childs play...

The world is my oyster... and I'm allergic to sea food.
My Background / Credentials

### #6 Robbie333

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Posted 10 January 2012 - 10:49 PM

Cryptozological Mascot, on 10 January 2012 - 10:40 PM, said:

Geez guys... you don't get this?  Childs play...

Easy for you to say, LOL. Math is not my strong point. I just don't "get it". I need to dismember it before I see the point. I taint' that bright, LOL.

Robbie James

### #7 KERIK182

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Posted 10 January 2012 - 11:22 PM

Saru, on 09 January 2012 - 03:25 PM, said:

Welcome to the forums.

Can you summarise this in laymen's terms and elaborate on what it is specifically you'd like to discuss ?
UMmmmm... I think the answer is 7.

### #8 sepulchrave

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Posted 11 January 2012 - 03:46 AM

Robbie333, on 10 January 2012 - 10:49 PM, said:

Easy for you to say, LOL. Math is not my strong point. I just don't "get it". I need to dismember it before I see the point. I taint' that bright, LOL.
I think it is child's play, albeit quite obfuscated and in poor English.

As far as I can tell, Mr. Biljanica is trying to create a logical constructor for the set of integers. (I.e. if we start with 1, how do we get to 2?) This isn't necessarily trivial, but it also isn't that important. Practical mathematics allows for the construction of arbitrary sets, so it doesn't really matter where the set of integers (or whole numbers, or reals, or complex numbers, or hypercomplex tensors, etc.) comes from, as long as you can explain what elements are within that set.

Providing a constructor for a set is mostly just the domain of abstract number theory.

As far as I can tell, the parts of Mr. Biljanica's work described here that aren't completely trivial are unexplained, unsupported, and non-rigorous, all of which are vital.

I would also like to ask to Mr. Biljanica:
• Can you define the "nature along" (perhaps you meant "natural line"?) in a rigorous way? You say "current mathematics does not recognize the concept of nature along" - but your figure 1 shows a common-place line segment.
• How is your work any different than a trivial attempt at reformulating the 100-years old and much more rigorous Principia Mathematica by Russell and Whitehead?
• Are you trying to formulate an internally consistent and complete logic, and if so how are you going to get around Godel's incompleteness theorem?

---------

If anyone reading this forum is interested in this sort of math, please refer to the Metamath proof explorer.

### #9 Englishgent

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Posted 11 January 2012 - 04:49 AM

I always admire people who can do this sort of mathematics. It's all double dutch to me
As long as i know how much change I should be given when I go shopping, i'm happy lol

edit....one thing that always amuses me though, is the way Amercans call it 'Math' when it's 'Maths'  We say 'mathematics (with an s) It's not 'mathematic'
Although maths is a shortened word it still applies to all types of maths, algebra, geometry etc. ...therefore needs to be plural

Edited by Englishgent, 11 January 2012 - 04:53 AM.

### #10 Robbie333

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Posted 11 January 2012 - 03:05 PM

sepulchrave, on 11 January 2012 - 03:46 AM, said:

I think it is child's play, albeit quite obfuscated and in poor English.

As far as I can tell, Mr. Biljanica is trying to create a logical constructor for the set of integers. (I.e. if we start with 1, how do we get to 2?) This isn't necessarily trivial, but it also isn't that important. Practical mathematics allows for the construction of arbitrary sets, so it doesn't really matter where the set of integers (or whole numbers, or reals, or complex numbers, or hypercomplex tensors, etc.) comes from, as long as you can explain what elements are within that set.

Providing a constructor for a set is mostly just the domain of abstract number theory.

As far as I can tell, the parts of Mr. Biljanica's work described here that aren't completely trivial are unexplained, unsupported, and non-rigorous, all of which are vital.

I would also like to ask to Mr. Biljanica:
• Can you define the "nature along" (perhaps you meant "natural line"?) in a rigorous way? You say "current mathematics does not recognize the concept of nature along" - but your figure 1 shows a common-place line segment.
• How is your work any different than a trivial attempt at reformulating the 100-years old and much more rigorous Principia Mathematica by Russell and Whitehead?
• Are you trying to formulate an internally consistent and complete logic, and if so how are you going to get around Godel's incompleteness theorem?

---------

If anyone reading this forum is interested in this sort of math, please refer to the Metamath proof explorer.

Thank you for clearing some of this up but either I cannot see his point or there cannot be one. Infinite, maybe. In other words there cannot be a definite because... I am still delving, LOL.

Robbie James

### #11 msbiljanica

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Posted 11 January 2012 - 04:33 PM

Saru, on 09 January 2012 - 03:25 PM, said:

Welcome to the forums.

Can you summarise this in laymen's terms and elaborate on what it is specifically you'd like to discuss ?
mathematics you learned in school are missing some parts that would be complete if you watch some processes in nature can not explain to enjoy their current mathematics,
example Z÷(10^n)=? ,
a={0,1,2,3,4,5,6,7,8,9} , b={1,2,3,4,5,6,7,8,9}
n=1 , Z÷10={...,(-2÷10),(-1÷10),(0÷10),(1÷10),(2÷10),...}={...,-0.2,-0.1,0,1,2,...}={Z,Z.b}
n=2 , Z÷100={Z,Z.b,Z.ab}
n=3 , Z÷1000={Z,Z.b,Zab,Zaab}
n=4 , Z÷10000={Z,Z.b,Z.ab,Zaab,Zaaab}
...
Z÷(10^n)=R  , a simple proof showing that the real number was the result of divisions of two integers
______________________________________________________________________________________
Presupposition-point numbers have their
The process:
P1-0 = (.0)
P2-1 = (.0,1)
P3-2 = (.0,1,2)
P4-3 = (.0,1,2,3)
P5-4 = (.0,1,2,3,4)
...
[S6]-point number
CM-I do not know the item number
_________________________________________________________________________
Presupposition-point numbers have opposite
The process:
P1-0 = (s.0)
P2-1 = (s.0, 1)
P3-2 = (s.0, 1.2)
P4-3 = (s.0, 1,2,3)
P5-4 = (s.0, 1,2,3,4)
...
[S7]-opposite point of
CM-I do not know the opposite point of
_______________________________________________________________________________
I will give you the following tasks that you can not solve the current knowledge of mathematics
1.You got along 20m (a), if you find along the (a) between 10m and 15m, get c.
...............
How can you write this in a shorter form:
2+10=12 , 2+15=17 , 2+16=18 , 2+20=22 , 2+23=25
2+25=27 , 2+29=31 , 2+30=32 , 2+35=37 , 2+37=39
2+38=40 , 2+40=42 , 2+44=46 , 2+45=47 , 2+47=49
2+50=52 , 2+51=53 , 2+55=57 , 2+56=58 , 2+58=60
2+60=62 , 2+64=66 , 2+65=67 , 2+70=72 , 2+71=73
2+74=76 , 2+75=77 , 2+80=82 , 2+82=84 , 2+83=85
2+92=94 , 2+101=103

### #12 sepulchrave

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Posted 12 January 2012 - 04:00 AM

msbiljanica, on 11 January 2012 - 04:33 PM, said:

mathematics you learned in school are missing some parts that would be complete if you watch some processes in nature can not explain to enjoy their current mathematics,
example Z÷(10^n)=? ,
a={0,1,2,3,4,5,6,7,8,9} , b={1,2,3,4,5,6,7,8,9}
n=1 , Z÷10={...,(-2÷10),(-1÷10),(0÷10),(1÷10),(2÷10),...}={...,-0.2,-0.1,0,1,2,...}={Z,Z.b}
n=2 , Z÷100={Z,Z.b,Z.ab}
n=3 , Z÷1000={Z,Z.b,Zab,Zaab}
n=4 , Z÷10000={Z,Z.b,Z.ab,Zaab,Zaaab}
...
Z÷(10^n)=R  , a simple proof showing that the real number was the result of divisions of two integers
No. Constructing an arbitrary real number out of an infinite series of integers does not count as "constructing reals out of integers".
This has been thought of before.

Obviously an arbitrary real number can be expressed in decimal (or any other) notation. However an arbitrary real number cannot be expressed in decimal (or any other) notation without complete knowledge of the generation of that real.

For example, what are the digits of pi? You can calculate them based on calculus and the definition of pi, but otherwise you can't figure them out.

If you want to express pi as a series of integers, you need infinite information.

msbiljanica, on 11 January 2012 - 04:33 PM, said:

...............
How can you write this in a shorter form:
2+10=12 , 2+15=17 , 2+16=18 , 2+20=22 , 2+23=25
2+25=27 , 2+29=31 , 2+30=32 , 2+35=37 , 2+37=39
2+38=40 , 2+40=42 , 2+44=46 , 2+45=47 , 2+47=49
2+50=52 , 2+51=53 , 2+55=57 , 2+56=58 , 2+58=60
2+60=62 , 2+64=66 , 2+65=67 , 2+70=72 , 2+71=73
2+74=76 , 2+75=77 , 2+80=82 , 2+82=84 , 2+83=85
2+92=94 , 2+101=103
I'd like to see it.

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Posted 12 January 2012 - 05:28 AM

sepulchrave, on 12 January 2012 - 04:01 AM, said:

No. Constructing an arbitrary real number out of an infinite series of integers does not count as "constructing reals out of integers".
This has been thought of before.

Obviously an arbitrary real number can be expressed in decimal (or any other) notation. However an arbitrary real number cannot be expressed in decimal (or any other) notation without complete knowledge of the generation of that real.

For example, what are the digits of pi? You can calculate them based on calculus and the definition of pi, but otherwise you can't figure them out.

If you want to express pi as a series of integers, you need infinite information.

<snip>

Indeed sepulchrave.

I didn't really want to get into this (have been involved in numerous "inventive" math threads in my time at UM), but I just wanted to give you the credit you deserve. Thanks for the insightful post. And you are indeed correct, PI has a very specific definition and you need exact knowledge of that before you can put the numbers of PI down. Anybody can come up with "new math", but until the time it proves itself useful it is just imaginary.

Cheers,

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### #14 msbiljanica

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Posted 12 January 2012 - 03:58 PM

sepulchrave -I'd like to see it.-when the time comes
original Serbian -  http://www.fileserve.com/file/8ecT3pr/Srđanova matematika 1-65.pdf

Presupposition-numbers are comparable with each other
The process:
P1-two numbers (a, b ) are comparable with each other - a> b, a = b, a <b, ).(=(>,=,<)
P2-three numbers (a, b, c) are comparable with each other
P3-four numbers (a, b, c, d) are comparable with each other
...
[S8]-comparability issues
CM knows the comparability of two numbers, the comparability of three numbers (a number comparable with the numbers b and c)
comparability of the other knows.
__________________________________________________ _________
Presupposition-number ranges number along
The process:
P1-image
P2-image
P3-image
...
[S9]-mobility of number
CM does not know the number of mobility

### #15 msbiljanica

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Posted 15 January 2012 - 04:18 PM

Presupposition-number and mobile number of a contact
The process:
P1-3 + (.0) 2 = 3
P2-3 + (.1) 2 = 3
P3-3 + (.2) 2 = 4
P4-3 +2 = 5, same as the current sum
CM knows only one type of addition is given as an axiom
____________________________________________________________
Presupposition-No I do not have a mobile contact number, except to point
The process:
P1-¤3(0)2¤
P2-¤3(1)2¤
P3-¤3(2)2¤
...
Next-gap number and mobile number have no contact, except to point
...
[S11]-gap numbers Gn = {¤a(b)c¤,...,¤ (b )...( d) e ¤}
[S12]-gap along the
_______________________________________________________________________
I will give you the following tasks that you can not solve the current knowledge of mathematics
1.You got along 20m (a), if you find along the (a) between 10m and 15m, get c.-
here is part of the solution to which the current mathematics does not know (how to describe the condition numbers c (image, # 11)
c=¤10m(5m)5m¤ - gap number

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