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srdanova math


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#31    bmk1245

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Posted 28 January 2012 - 11:50 AM

View Postmsbiljanica, on 28 January 2012 - 08:28 AM, said:

srcko ab, abc , 55={5,10,15,20,...} ,22222={2,4,6,...,220,222}
:blink:

Thanks, I guess...

coombacoombla(x2)=2x... Think about it.

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#32    badeskov

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Posted 28 January 2012 - 12:42 PM

Uhm, ok.

So what does N2M  mean in your math? I am guessing  N2M={N, N+2, N+4,...,M}. If correct, great, so now you have redefined how we denote sets. So, how do you now denote variables? Like the variables N1, N2, M19 etc?

Cheers,
Badeskov

Edited by badeskov, 28 January 2012 - 01:30 PM.

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#33    badeskov

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Posted 28 January 2012 - 12:44 PM

View Postbmk1245, on 28 January 2012 - 11:50 AM, said:

:blink:

Thanks, I guess...

coombacoombla(x2)=2x... Think about it.

I rather like it. You know, bmk, d/dx is rather boring and dull. :P Also, coombacoombla is a nice long and good sounding word, it sooo takes the emphasis over boring numbers in long equations ;)

Cheers,
Badeskov

"Life is not a journey to the grave with the intention to arrive safely in a pretty and well-preserved body, but rather to skid in broadside, thoroughly used, totally worn out, and loudly proclaiming: Wow!! What a ride!". Said to to Dean Karnazes by a running buddy.

#34    bmk1245

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Posted 28 January 2012 - 04:21 PM

View Postbadeskov, on 28 January 2012 - 12:44 PM, said:

I rather like it. You know, bmk, d/dx is rather boring and dull. :P Also, coombacoombla is a nice long and good sounding word, it sooo takes the emphasis over boring numbers in long equations ;)

Cheers,
Badeskov
Math (as well as other scientific) books would be unliftable

:D

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#35    msbiljanica

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Posted 29 January 2012 - 08:50 AM

Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete
Process:
P1 4-(.0)2=2
P2 4-(.1)2=1(2)1 image
P3 4-(.2)2=2
P4 4-(.3)2=3(1)1
P5 4-(.4)2=4(0)2
Attached File  a12.png   40.76K   1 downloads
General form
a-(.0)b=c
a-(.1)b=c
...
a-(.d)b=c
[S19]-subtraction
CM-only form a-(s.0/s.0)b=c , others do not know , axiom
_______________________________________________________________________
Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f
Process:
P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017
P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321
...
General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e
a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f
a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...
[S20]-right inequality addition
CM-[S20]-know


#36    badeskov

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Posted 30 January 2012 - 05:29 AM

Sooo, care to elaborate on how you denote variables in your math?

Cheers,
Badeskov

"Life is not a journey to the grave with the intention to arrive safely in a pretty and well-preserved body, but rather to skid in broadside, thoroughly used, totally worn out, and loudly proclaiming: Wow!! What a ride!". Said to to Dean Karnazes by a running buddy.

#37    msbiljanica

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Posted 30 January 2012 - 10:10 AM

Presupposition-Two ( more) addition (left and right inequalities) can be short to write
Process:
P1 3+(.013)4=y , 3+(.013)4>y ,3+(.013)4<y
P2 8+(.228)5=y , 8+(.228)5>y ,8+(.228)5<y
...
General form - a+(.bcd)e=y ,a+(.bcd)e>y , a+(.bcd)e<y
a+(.bcd_e)f=y , a+(.bcd_e)f>y , a+(.bcd_e)f<y ,...
[S21]-function addition
CM-[S21]-does no know
______________________________________________________
Presupposition-Gap number ( value z) is a variable (same value) with the gaps that is constant
Process:
P1 5(2)0,4(2)1,3(2)2,2(2)3,1(2)4,0(2)5 --5(2)

P2 3(2)0,2(2)1,1(2)2,0(2)3
2(2)0,1(2)1.0(2)2
1(2)0,0(2)1
0(2)0 --013(2)


2(2)0,1(2)1,0(2)2
3(2)0,2(2)1,1(2)2,0(2)3
...
21(2)

[S22]-variability of z number
CM-[S22]-does no know
_______________________________________-
PDF - http://www.mediafire...jzheej0qu93jjkm


#38    badeskov

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Posted 30 January 2012 - 11:06 PM

View Postbadeskov, on 30 January 2012 - 05:29 AM, said:

Sooo, care to elaborate on how you denote variables in your math?

I guess that is a no then....

Cheers,
Badeskov

"Life is not a journey to the grave with the intention to arrive safely in a pretty and well-preserved body, but rather to skid in broadside, thoroughly used, totally worn out, and loudly proclaiming: Wow!! What a ride!". Said to to Dean Karnazes by a running buddy.

#39    sepulchrave

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Posted 31 January 2012 - 12:32 AM

View Postbadeskov, on 30 January 2012 - 11:06 PM, said:

I guess that is a no then....
Yeah, it seems like msbiljanica is just dumping his ``mathematics manifesto'' into google translate and then throwing it up on the forums, rather than actively explaining or discussing the content of his posts.

I mean since the OP stated that current mathematics were ``limited and sinful'' (emphasis mine) - which I am assuming (or hoping!) was just a poor translation - I wouldn't hold my breath for any extra insight into his existing posts.


#40    badeskov

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Posted 31 January 2012 - 01:09 AM

View Postsepulchrave, on 31 January 2012 - 12:32 AM, said:

Yeah, it seems like msbiljanica is just dumping his ``mathematics manifesto'' into google translate and then throwing it up on the forums, rather than actively explaining or discussing the content of his posts.

I mean since the OP stated that current mathematics were ``limited and sinful'' (emphasis mine) - which I am assuming (or hoping!) was just a poor translation - I wouldn't hold my breath for any extra insight into his existing posts.

I fear that you are correct in your assessment - not unexpectedly, though. And  I wonder too how current mathematics are sinful. I have heard mathematics being called much, but I think sinful is a first.

Cheers,
Badeskov



"Life is not a journey to the grave with the intention to arrive safely in a pretty and well-preserved body, but rather to skid in broadside, thoroughly used, totally worn out, and loudly proclaiming: Wow!! What a ride!". Said to to Dean Karnazes by a running buddy.

#41    msbiljanica

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Posted 31 January 2012 - 10:18 AM

Presupposition-Translation of gap number in the variability z ( with constant gap ) can addition
(s.0)
Process:
P1 3(2)3+(.z)4(2)4=6(2)+(.z)8(2)=14(2)
P2 1(6)1(9)1+(.z)3(6)2(9)1=3(6)(9)+(.z)6(6)(9)=9(6)(9)
...
General form a(b)c+(.z)d(b)e=f(b )+(.z)g(b )=h(b ) ...
[S23]-z addition
CM-[S23]-does no know
__________________________________________
Presupposition-Translation of gap number in the variability z ( with constant gap ) can subtraction
(s.0/s.0)
Process:
P1 3(2)3-(.z)1(2)1=6(2)-(.z)2(2)=4(2)
P2 3(6)2(9)1-(.z)1(6)1(9)1=6(6)(9)-(.z)3(6)(9)=3(6)(9)
...
General form a(b)c-(.z)d(b)e=f(b )-(.z)g(b )=h(b ) ...
[S24]-z subtraction
CM-[S24]-does no know


#42    msbiljanica

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Posted 01 February 2012 - 10:38 AM

Presupposition-In the expression a-(.b)c=d , d+(s.0))11 or d+(s.0)number (more) from 11
and d+(.z)11e or d+(.z) number ( more ) from 11e , e={(f),(f)(f),(f)(f)(f),...}
Process:
P1 4-(.2)2=2+(s.0)11 , 4-(.2)2<31
4-(.3)2=1(2)1+(.z)11(2) , 4-(.3)2<2(2)+(.z)11(2) , 4-(.3)2<31(2)
P2 4-(.2)2=2+(s.0)4 , 4-(.2)2<6
4-(.3)2=1(2)1+(.z)7(2) , 4-(.3)2<2(2)+(.z)7(2), 4-(.3)<9(2)
...
General form - a-(.b)c=d-(s.0)11 ,a+(s.b)c<g1
a-(.b)c=d+(s.0)g , a+(.b)c<l
a-(.b)c=d+(s.0)kpg , a+(.b)c<hij ...
a-(.b)c=d+(.z)11e , a-(.b)c<se+(.z)11e , a+(s.b)c<g1e
a-(.b)c=d+(.z)ge , a-(.b)c<se+(.z)ge , a+(.b)c<le
a-(.b)c=d+(.z)kpge , a-(.b)c<se+(.z)kpge , a+(.b)c<hije ...
[S25]-left inequality subtraction
CM-[S25]-know , forms without any gaps numbers not known
____________________________________________________________________
Presupposition-In the expression a-(.b)c=d , d-(s.0/s.0))11p or d+(s.0/s.0)number (more) from 11p
and d-(.z)11pe or d-(.z) number ( more ) from 11e , e={(f),(f)(f),(f)(f)(f),...}
Process:
P1 4-(.2)2=2-(s.0/s.0))112 , 4-(.2)2>011
4-(.3)2=1(2)1-(.z)211(2) , 4-(.3)2>2(2)-(.z)211(2) , 4-(.3)2>011(2)
P2 4-(.2)2=2-(s.0/s.0))1 , 4-(.2)2>1
4-(.3)2=1(2)1-(.z)1(2) , 4-(.3)2>2(2)-(.z)1(2) , 4-(.3)>1(2)
...
General form - a-(.b)c=d-(s.0/s.0)11p ,a-(s.b)c>g1l
a-(.b)c=d-(s.0/s.0))g , a-(.b)c>l
a-(.b)c=d-(s.0/s.0))ksg , a-(.b)c>hij ...
a-(.b)c=d-(.z)11pe , a-(.b)c>se-(.z)11pe , a-(s.b)c>g1ke
a-(.b)c=d-(.z)ge , a-(.b)c>se-(.z)ge , a-(.b)c>le
a-(.b)c=d-(.z)kpge , a-(.b)c>se-(.z)kpge , a-(.b)c>hije ...
[S26]-right inequality subtraction
CM-[S26]-know , forms without any gaps numbers not known


#43    msbiljanica

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Posted 02 February 2012 - 09:39 AM

Presupposition-Two ( more) subtraction (left and right inequalities) can be short to write
Process:
P1 7-(.013)4=y , 7-(.013)4>y ,7-(.013)4<y
P2 8-(.228)5=y , 8-(.228)5>y ,8-(.228)5<y
...
General form a-(.bcd)e=y ,a-(.bcd)e>y , a-(.bcd)e<y
a-(.bcd_e)f=y , a-(.bcd_e)f>y , a-(.bcd_e)f<y ,...
[S27]-function subtraction
CM-[S27]-does no know
_____________________________________
Presupposition-Parts number (a) and mobile number (b ) have a contact , contact remains , the
rest is delete
Process:
Attached File  a13.png   45.6K   0 downloads
P1 4 - (.0)2=2
P2 4 - (.1)2=2 image
P3 4 - (.2)2=2
P4 4 - (.3)2=1
P5 4 - (.4)2=1
General form
a - (.0)b=c
a - (.1)b=c
...
a - (.d)b=c

[S28]-opposite subtraction
CM-[S28]-does no know
-sign for. opposite subtraction (when you download the following PDF you will see how it looks)


#44    msbiljanica

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Posted 03 February 2012 - 12:27 PM

3.how to solve this current knowledge of mathematics:
along a (20m) ,deleted between 10 m and 15 m (b=5m) , wet get c
20m-(.5m)=10m(5m)5m
___________________________________________________
Presupposition-In the expression a - (.b)c=d , d+(s.0))11 or d+(s.0)number (more) from 11
and d+(.z)11e or d+(.z) number ( more ) from 11e , e={(f),(f)(f),(f)(f)(f),...}
Process:
P1 5 - (.0)5=5+(s.0)11 , 5 - (.0)5<61
2(2)2 - (.1)1(1)2=1(2)1+(.z)11(2)
2(2)2 - (.1)1(1)2<2(2)+(.z)11(2) , 2(2)2 - (.1)1/1)2<31(2)
P2 5 - (.0)5=5+(s.0)4 , 5 - (.0)5<9
2(2)2 - (.1)1(1)2=1(2)1+(.z)7(2)
2(2)2 - (.1)1(1)2)<2(2)+(.z)7(2), 2(2)2 - (.1)1(1)2<9(2)
...
General form a - (.b)c=d-(s.0)11 ,a - (s.b)c<g1
a - (.b)c=d+(s.0)g , a - (.b)c<l
a - (.b)c=d+(s.0)kpg , a - (.b)c<hij ...
a -(.b)c=d+(.z)11e , a - (.b)c<se+(.z)11e , a - (s.b)c<g1e
a - (.b)c=d+(.z)ge , a - (.b)c<se+(.z)ge , a - (.b)c<le
a - (.b)c=d+(.z)kpge , a - (.b)c<se+(.z)kpge , a - (.b)c<hije ...
[S29]-left inequality opposite subtraction
CM-[S29]-does no know
_________________________________
Presupposition-In the expression a - (.b)c=d , d-(s.0/s.0))11p or d+(s.0/s.0)number (more) from
11p and d-(.z)11pe or d-(.z) number ( more ) from 11e , e={(f),(f)(f),(f)(f)(f),...}
Process:
P1 5 - (.0)5=5 -(s.0/s.0))115 , 5 - (.0)5>014
2(2)2 - (.1)1(1)2=1(2)1-(.z)211(2)
2(2)2 - (.1)1(1)2>2(2)-(.z)211(2) , 2(2)2 - (.1)1(1)2>011(2)
P2 5 - (.0)5=5-(s.0/s.0))1 , 5 - (.0)5>1
2(2)2 - (.1)1(1)2=1(2)1-(.z)1(2)
2(2)2 - (.1)1(1)2>2(2)-(.z)1(2) , 2(2)2 - (.1)1(1)2>1(2)
...
General form a - (.b)c=d-(s.0/s.0)11p ,a - (s.b)c>g1l
a - (.b)c=d-(s.0/s.0))g , a - (.b)c>l
a - (.b)c=d-(s.0/s.0))ksg , a - (.b)c>hij ...
a - (.b)c=d-(.z)11pe , a - (.b)c>se-(.z)11pe , a - (s.b)c>g1ke
a - (.b)c=d-(.z)ge , a - (.b)c>se-(.z)ge , a - (.b)c>le
a - (.b)c=d-(.z)kpge , a - (.b)c>se-(.z)kpge , a - (.b)c>hije ...
[S30]-right inequality opposite subtraction
CM-[S30]-does no know
__________________________________-
PDF - http://www.mediafire...qle11bvr2yuey9o


#45    msbiljanica

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Posted 04 February 2012 - 04:34 PM

Presupposition-Two ( more) opposite subtraction (left and right inequalities) can be short to write
Process:
P1 7 - (.013)4=y , 7 - (.013)4>y ,7 - (.013)4<y
P2 8 - (.228)5=y ,  8 - (.228)5>y ,8 - (.228)5<y
...
General form  a - (.bcd)e=y ,a - (.bcd)e>y , a - (.bcd)e<y
a - (.bcd_e)f=y , a - (.bcd_e)f>y , a - (.bcd_e)f<y ,...
[S31]-function opposite subtraction
CM-[S31]-does no know
__________________________________
Presupposition-Two ( more) addition the same number can be written in shorted form
Process:
P1 a+(s.c)a=a(s.c)2 , a(s.c)b
P2 a+(s.c)a+(s.c)a=a(s.c)3 , a(s.c)b
P3 a+(s.c)a+(s.c)a+(s.c)a=a(s.c)4 , a(s.c)b
...
[S32]-multiplication
CM-[S32]-know , axiom
Presupposition-In terms a(s.c)b , b can be number 0 (1)
Process:
P1 a(s.c)0
P2 a(s.c)1
[S32a]-multiplication-amendment





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