Question

Verified by Toppr

Correct option is

$P_{water}=p_{B}=85.140$ kPa

$P_{liquid}=p_{A}=(99.652β85.140)$ kPa

$=14.512$ kPa

and $m_{B}m_{A}β=11.27β$

or $m_{B}m_{A}β=p_{B}M_{B}p_{A}M_{A}β$

or, $M_{A}=(m_{B}m_{A}β)(p_{A}p_{B}M_{B}β)$

$M_{A}=1.27Γ(14.512ΒkPa85.140kPaΓ18ΒgΒmol_{β1}β)$

$M_{A}β134.1ΒgΒmol_{β1}$

Solve any question of Solutions with:-

0

0