bmk1245 Posted January 27, 2012 #26 Share Posted January 27, 2012 (edited) Mr. msbiljanica, start you can english wayno understand thou? Seriously, try a little bit harder to express your thoughts in the way everyone could understand. And what a hell is srcko? Cheese in circus? And, BTW, will your "new math" help me solve system of differential equations easier than "old math"? Edit: grammar Edited January 27, 2012 by bmk1245 Link to comment Share on other sites More sharing options...
Alienated Being Posted January 28, 2012 #27 Share Posted January 28, 2012 Just because some find to be easier to understand and demonstrate than others, that doesn't make it child's play. I am sure that Stephen Hawking would find calculus to be child's play... Link to comment Share on other sites More sharing options...
msbiljanica Posted January 28, 2012 Author #28 Share Posted January 28, 2012 Mr. msbiljanica, start you can english wayno understand thou? Seriously, try a little bit harder to express your thoughts in the way everyone could understand. And what a hell is srcko? Cheese in circus? And, BTW, will your "new math" help me solve system of differential equations easier than "old math"? Edit: grammar srcko ab, abc , 55={5,10,15,20,...} ,22222={2,4,6,...,220,222} Link to comment Share on other sites More sharing options...
msbiljanica Posted January 28, 2012 Author #29 Share Posted January 28, 2012 bmk1245, on 27 January 2012 - 11:14 PM, said: application modeler forum - because I had problems with an Internet connection, to delete the previous post (to leave only one) _________________________________________________ Presupposition-Two ( more ) srcko have the first ( last) common number Process: P1 10530 and 3330 , 10533(_30) P2 4444 and 441094 and 44256 , 44(_44_)1094256 ... General form -abcd(_e) , ab(_c_)defg , ... [s17]-two ( more) first-last srcko CM-[s17]-does no know ______________________________________________________ Presupposition-In the expression a+(.b)c=d , d+(s.0)11 or d+(s.0)number (more) from 11 Process: P1 3+(.s.0)5=8+(s.0)11 , 3+(s.0)5<91 P2 5+(.0)5=5+(s.0)224 , 5+(.0)5<729 ... General form - a+(.b)c=d+(s.0)11 ,a+(s.b)c<e1 a+(.b)c=d+(s.0)e , a+(.b)c<f a+(.b)c=d+(s.0)efg , a+(.b)c<hij ... [s18]-left inequality CM-[s18]-know _______________________________________ 2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40, 2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 , 2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94 srcko 5550={5,10,15,20,25,30,35,40,45,50} 38350={38,41,44,47,50} 501090={50,60,70,80,90} 50792={50,57,64,71,78,85,92} two(more) first-last srcko 55383(_50_)1090792 remains part of the function, when we come to it Link to comment Share on other sites More sharing options...
bmk1245 Posted January 28, 2012 #30 Share Posted January 28, 2012 Just because some find to be easier to understand and demonstrate than others, that doesn't make it child's play. I am sure that Stephen Hawking would find calculus to be child's play... Well, if Stephen Hawking would rename differential operator (d/dx) into coombacoombla and call it new math, that would be child's play. I can come up with dozen symbols for sum operator, that wouldn't make my math new, nor any better. Link to comment Share on other sites More sharing options...
bmk1245 Posted January 28, 2012 #31 Share Posted January 28, 2012 srcko ab, abc , 55={5,10,15,20,...} ,22222={2,4,6,...,220,222} Thanks, I guess... coombacoombla(x2)=2x... Think about it. Link to comment Share on other sites More sharing options...
badeskov Posted January 28, 2012 #32 Share Posted January 28, 2012 (edited) Uhm, ok. So what does N2M mean in your math? I am guessing N2M={N, N+2, N+4,...,M}. If correct, great, so now you have redefined how we denote sets. So, how do you now denote variables? Like the variables N1, N2, M19 etc? Cheers, Badeskov Edited January 28, 2012 by badeskov Link to comment Share on other sites More sharing options...
badeskov Posted January 28, 2012 #33 Share Posted January 28, 2012 Thanks, I guess... coombacoombla(x2)=2x... Think about it. I rather like it. You know, bmk, d/dx is rather boring and dull. Also, coombacoombla is a nice long and good sounding word, it sooo takes the emphasis over boring numbers in long equations Cheers, Badeskov Link to comment Share on other sites More sharing options...
bmk1245 Posted January 28, 2012 #34 Share Posted January 28, 2012 I rather like it. You know, bmk, d/dx is rather boring and dull. Also, coombacoombla is a nice long and good sounding word, it sooo takes the emphasis over boring numbers in long equations Cheers, Badeskov Math (as well as other scientific) books would be unliftable Link to comment Share on other sites More sharing options...
msbiljanica Posted January 29, 2012 Author #35 Share Posted January 29, 2012 Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete Process: P1 4-(.0)2=2 P2 4-(.1)2=¤1(2)1¤ image P3 4-(.2)2=2 P4 4-(.3)2=¤3(1)1¤ P5 4-(.4)2=¤4(0)2¤ General form a-(.0)b=c a-(.1)b=c ... a-(.d)b=c [s19]-subtraction CM-only form a-(s.0/s.0)b=c , others do not know , axiom _______________________________________________________________________ Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f Process: P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017 P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321 ... General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ... [s20]-right inequality addition CM-[s20]-know Link to comment Share on other sites More sharing options...
badeskov Posted January 30, 2012 #36 Share Posted January 30, 2012 Sooo, care to elaborate on how you denote variables in your math? Cheers, Badeskov Link to comment Share on other sites More sharing options...
msbiljanica Posted January 30, 2012 Author #37 Share Posted January 30, 2012 Presupposition-Two ( more) addition (left and right inequalities) can be short to write Process: P1 3+(.013)4=y , 3+(.013)4>y ,3+(.013)4<y P2 8+(.228)5=y , 8+(.228)5>y ,8+(.228)5<y ... General form - a+(.bcd)e=y ,a+(.bcd)e>y , a+(.bcd)e<y a+(.bcd_e)f=y , a+(.bcd_e)f>y , a+(.bcd_e)f<y ,... [s21]-function addition CM-[s21]-does no know ______________________________________________________ Presupposition-Gap number ( value z) is a variable (same value) with the gaps that is constant Process: P1 ¤5(2)0¤,¤4(2)1¤,3(2)2¤,¤2(2)3¤,¤1(2)4¤,¤0(2)5¤ --5¤¤(2) P2 ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤ ¤2(2)0¤,¤1(2)1¤.¤0(2)2¤ ¤1(2)0¤,¤0(2)1¤ ¤0(2)0¤ --013¤¤(2) ¤2(2)0¤,¤1(2)1¤,¤0(2)2¤ ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤ ... 21¤¤(2) [s22]-variability of z number CM-[s22]-does no know _______________________________________- PDF - http://www.mediafire.com/?jzheej0qu93jjkm Link to comment Share on other sites More sharing options...
badeskov Posted January 30, 2012 #38 Share Posted January 30, 2012 Sooo, care to elaborate on how you denote variables in your math? I guess that is a no then.... Cheers, Badeskov Link to comment Share on other sites More sharing options...
sepulchrave Posted January 31, 2012 #39 Share Posted January 31, 2012 I guess that is a no then.... Yeah, it seems like msbiljanica is just dumping his ``mathematics manifesto'' into google translate and then throwing it up on the forums, rather than actively explaining or discussing the content of his posts. I mean since the OP stated that current mathematics were ``limited and sinful'' (emphasis mine) - which I am assuming (or hoping!) was just a poor translation - I wouldn't hold my breath for any extra insight into his existing posts. Link to comment Share on other sites More sharing options...
badeskov Posted January 31, 2012 #40 Share Posted January 31, 2012 Yeah, it seems like msbiljanica is just dumping his ``mathematics manifesto'' into google translate and then throwing it up on the forums, rather than actively explaining or discussing the content of his posts. I mean since the OP stated that current mathematics were ``limited and sinful'' (emphasis mine) - which I am assuming (or hoping!) was just a poor translation - I wouldn't hold my breath for any extra insight into his existing posts. I fear that you are correct in your assessment - not unexpectedly, though. And I wonder too how current mathematics are sinful. I have heard mathematics being called much, but I think sinful is a first. Cheers, Badeskov Link to comment Share on other sites More sharing options...
msbiljanica Posted January 31, 2012 Author #41 Share Posted January 31, 2012 Presupposition-Translation of gap number in the variability z ( with constant gap ) can addition (s.0) Process: P1 ¤3(2)3¤+(.z)¤4(2)4=6¤¤(2)+(.z)8¤¤(2)=14¤¤(2) P2 ¤1(6)1(9)1¤+(.z)¤3(6)2(9)1¤=3¤¤(6)(9)+(.z)6¤¤(6)(9)=9¤¤(6)(9) ... General form ¤a(b)c¤+(.z)¤d(b)e¤=f¤¤(b )+(.z)g¤¤(b )=h¤¤(b ) ... [s23]-z addition CM-[s23]-does no know __________________________________________ Presupposition-Translation of gap number in the variability z ( with constant gap ) can subtraction (s.0/s.0) Process: P1 ¤3(2)3¤-(.z)¤1(2)1=6¤¤(2)-(.z)2¤¤(2)=4¤¤(2) P2 ¤3(6)2(9)1¤-(.z)¤1(6)1(9)1¤=6¤¤(6)(9)-(.z)3¤¤(6)(9)=3¤¤(6)(9) ... General form ¤a(b)c¤-(.z)¤d(b)e¤=f¤¤(b )-(.z)g¤¤(b )=h¤¤(b ) ... [s24]-z subtraction CM-[s24]-does no know Link to comment Share on other sites More sharing options...
msbiljanica Posted February 1, 2012 Author #42 Share Posted February 1, 2012 Presupposition-In the expression a-(.b)c=d , d+(s.0))11 or d+(s.0)number (more) from 11 and d+(.z)11¤¤e or d+(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...} Process: P1 4-(.2)2=2+(s.0)11 , 4-(.2)2<31 4-(.3)2=¤1(2)1¤+(.z)11¤¤(2) , 4-(.3)2<2¤¤(2)+(.z)11¤¤(2) , 4-(.3)2<31¤¤(2) P2 4-(.2)2=2+(s.0)4 , 4-(.2)2<6 4-(.3)2=¤1(2)1¤+(.z)7¤¤(2) , 4-(.3)2<2¤¤(2)+(.z)7¤¤(2), 4-(.3)<9¤¤(2) ... General form - a-(.b)c=d-(s.0)11 ,a+(s.b)c<g1 a-(.b)c=d+(s.0)g , a+(.b)c<l a-(.b)c=d+(s.0)kpg , a+(.b)c<hij ... a-(.b)c=d+(.z)11¤¤e , a-(.b)c<s¤¤e+(.z)11¤¤e , a+(s.b)c<g1¤¤e a-(.b)c=d+(.z)g¤¤e , a-(.b)c<s¤¤¤e+(.z)g¤¤e , a+(.b)c<l¤¤e a-(.b)c=d+(.z)kpg¤¤e , a-(.b)c<s¤¤e+(.z)kpg¤¤e , a+(.b)c<hij¤¤e ... [s25]-left inequality subtraction CM-[s25]-know , forms without any gaps numbers not known ____________________________________________________________________ Presupposition-In the expression a-(.b)c=d , d-(s.0/s.0))11p or d+(s.0/s.0)number (more) from 11p and d-(.z)11p¤¤e or d-(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...} Process: P1 4-(.2)2=2-(s.0/s.0))112 , 4-(.2)2>011 4-(.3)2=¤1(2)1¤-(.z)211¤¤(2) , 4-(.3)2>2¤¤(2)-(.z)211¤¤(2) , 4-(.3)2>011¤¤(2) P2 4-(.2)2=2-(s.0/s.0))1 , 4-(.2)2>1 4-(.3)2=¤1(2)1¤-(.z)1¤¤(2) , 4-(.3)2>2¤¤(2)-(.z)1¤¤(2) , 4-(.3)>1¤¤(2) ... General form - a-(.b)c=d-(s.0/s.0)11p ,a-(s.b)c>g1l a-(.b)c=d-(s.0/s.0))g , a-(.b)c>l a-(.b)c=d-(s.0/s.0))ksg , a-(.b)c>hij ... a-(.b)c=d-(.z)11p¤¤e , a-(.b)c>s¤¤e-(.z)11p¤¤e , a-(s.b)c>g1k¤¤e a-(.b)c=d-(.z)g¤¤e , a-(.b)c>s¤¤e-(.z)g¤¤e , a-(.b)c>l¤¤e a-(.b)c=d-(.z)kpg¤¤e , a-(.b)c>s¤¤e-(.z)kpg¤¤e , a-(.b)c>hij¤¤e ... [s26]-right inequality subtraction CM-[s26]-know , forms without any gaps numbers not known Link to comment Share on other sites More sharing options...
msbiljanica Posted February 2, 2012 Author #43 Share Posted February 2, 2012 Presupposition-Two ( more) subtraction (left and right inequalities) can be short to write Process: P1 7-(.013)4=y , 7-(.013)4>y ,7-(.013)4<y P2 8-(.228)5=y , 8-(.228)5>y ,8-(.228)5<y ... General form a-(.bcd)e=y ,a-(.bcd)e>y , a-(.bcd)e<y a-(.bcd_e)f=y , a-(.bcd_e)f>y , a-(.bcd_e)f<y ,... [s27]-function subtraction CM-[s27]-does no know _____________________________________ Presupposition-Parts number (a) and mobile number (b ) have a contact , contact remains , the rest is delete Process: P1 4 - (.0)2=2 P2 4 - (.1)2=2 image P3 4 - (.2)2=2 P4 4 - (.3)2=1 P5 4 - (.4)2=1 General form a - (.0)b=c a - (.1)b=c ... a - (.d)b=c [s28]-opposite subtraction CM-[s28]-does no know -sign for. opposite subtraction (when you download the following PDF you will see how it looks) Link to comment Share on other sites More sharing options...
msbiljanica Posted February 3, 2012 Author #44 Share Posted February 3, 2012 3.how to solve this current knowledge of mathematics: along a (20m) ,deleted between 10 m and 15 m (b=5m) , wet get c 20m-(.5m)=¤10m(5m)5m¤ ___________________________________________________ Presupposition-In the expression a - (.b)c=d , d+(s.0))11 or d+(s.0)number (more) from 11 and d+(.z)11¤¤e or d+(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...} Process: P1 5 - (.0)5=5+(s.0)11 , 5 - (.0)5<61 ¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤+(.z)11¤¤(2) ¤2(2)2¤ - (.1)¤1(1)2¤<2¤¤(2)+(.z)11¤¤(2) , ¤2(2)2¤ - (.1)¤1/1)2¤<31¤¤(2) P2 5 - (.0)5=5+(s.0)4 , 5 - (.0)5<9 ¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤+(.z)7¤¤(2) ¤2(2)2¤ - (.1)¤1(1)2)¤<2¤¤(2)+(.z)7¤¤(2), ¤2(2)2¤ - (.1)¤1(1)2¤<9¤¤(2) ... General form a - (.b)c=d-(s.0)11 ,a - (s.b)c<g1 a - (.b)c=d+(s.0)g , a - (.b)c<l a - (.b)c=d+(s.0)kpg , a - (.b)c<hij ... a -(.b)c=d+(.z)11¤¤e , a - (.b)c<s¤¤e+(.z)11¤¤e , a - (s.b)c<g1¤¤e a - (.b)c=d+(.z)g¤¤e , a - (.b)c<s¤¤¤e+(.z)g¤¤e , a - (.b)c<l¤¤e a - (.b)c=d+(.z)kpg¤¤e , a - (.b)c<s¤¤e+(.z)kpg¤¤e , a - (.b)c<hij¤¤e ... [s29]-left inequality opposite subtraction CM-[s29]-does no know _________________________________ Presupposition-In the expression a - (.b)c=d , d-(s.0/s.0))11p or d+(s.0/s.0)number (more) from 11p and d-(.z)11p¤¤e or d-(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...} Process: P1 5 - (.0)5=5 -(s.0/s.0))115 , 5 - (.0)5>014 ¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤-(.z)211¤¤(2) ¤2(2)2¤ - (.1)¤1(1)2¤>2¤¤(2)-(.z)211¤¤(2) , ¤2(2)2¤ - (.1)¤1(1)2¤>011¤¤(2) P2 5 - (.0)5=5-(s.0/s.0))1 , 5 - (.0)5>1 ¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤-(.z)1¤¤(2) ¤2(2)2¤ - (.1)¤1(1)2¤>2¤¤(2)-(.z)1¤¤(2) , ¤2(2)2¤ - (.1)¤1(1)2¤>1¤¤(2) ... General form a - (.b)c=d-(s.0/s.0)11p ,a - (s.b)c>g1l a - (.b)c=d-(s.0/s.0))g , a - (.b)c>l a - (.b)c=d-(s.0/s.0))ksg , a - (.b)c>hij ... a - (.b)c=d-(.z)11p¤¤e , a - (.b)c>s¤¤e-(.z)11p¤¤e , a - (s.b)c>g1k¤¤e a - (.b)c=d-(.z)g¤¤e , a - (.b)c>s¤¤e-(.z)g¤¤e , a - (.b)c>l¤¤e a - (.b)c=d-(.z)kpg¤¤e , a - (.b)c>s¤¤e-(.z)kpg¤¤e , a - (.b)c>hij¤¤e ... [s30]-right inequality opposite subtraction CM-[s30]-does no know __________________________________- PDF - http://www.mediafire.com/?qle11bvr2yuey9o Link to comment Share on other sites More sharing options...
msbiljanica Posted February 4, 2012 Author #45 Share Posted February 4, 2012 Presupposition-Two ( more) opposite subtraction (left and right inequalities) can be short to write Process: P1 7 - (.013)4=y , 7 - (.013)4>y ,7 - (.013)4<y P2 8 - (.228)5=y , 8 - (.228)5>y ,8 - (.228)5<y ... General form a - (.bcd)e=y ,a - (.bcd)e>y , a - (.bcd)e<y a - (.bcd_e)f=y , a - (.bcd_e)f>y , a - (.bcd_e)f<y ,... [s31]-function opposite subtraction CM-[s31]-does no know __________________________________ Presupposition-Two ( more) addition the same number can be written in shorted form Process: P1 a+(s.c)a=a×(s.c)2 , a×(s.c)b P2 a+(s.c)a+(s.c)a=a×(s.c)3 , a×(s.c)b P3 a+(s.c)a+(s.c)a+(s.c)a=a×(s.c)4 , a×(s.c)b ... [s32]-multiplication CM-[s32]-know , axiom Presupposition-In terms a×(s.c)b , b can be number 0 (1) Process: P1 a×(s.c)0 P2 a×(s.c)1 [s32a]-multiplication-amendment Link to comment Share on other sites More sharing options...
badeskov Posted February 4, 2012 #46 Share Posted February 4, 2012 <snipped uninteresting stuff> Seriously, why don't you get a blog? You obviously have no interest in discussing your so called "new math", which makes it rather uninteresting for a discussion forum - not that this "new math" contributes anything anyways. You can't even tell me how you denote variables with indices, which is a rather large flaw. Good grief. Cheers, Badeskov Link to comment Share on other sites More sharing options...
msbiljanica Posted February 5, 2012 Author #47 Share Posted February 5, 2012 Presupposition-In terms a×(s.c)b , multiplication Process: P1 4×(s.0)4=16 P2 4×(s.1)4=13 image P3 4×(s.2)4=10 P4 4×(s.3)4=7 P5 4×(s.4)4=4 P1 ¤1(2)1¤×(s.0)4=¤1(2)2(2)2(2)2(2)1¤ P2 ¤1(2)1¤×(s.1)4=¤1(2)1(2)1(2)1(2)1¤ image P3 ¤1(2)1¤×(s.2)4=¤1(1)6(1)1¤ P4 ¤1(2)1¤×(s.3)4=7 P5 ¤1(2)1¤×(s.4)4=¤1(2)1¤ General form a×(s.0)b=c a×(s.1)b=c ... a×(c.d)b=c [s32b]-multiplication CM-[s32b]-know a×(s.0)b other do not know , forms withuut any gaps numbers not known Link to comment Share on other sites More sharing options...
badeskov Posted February 5, 2012 #48 Share Posted February 5, 2012 Sigh..... Link to comment Share on other sites More sharing options...
msbiljanica Posted February 6, 2012 Author #49 Share Posted February 6, 2012 PDF - http://www.mediafire.com/?ffy4ravu1gw4xkd ___________________________________________ Presupposition-The numbers are multiplication , where a contact is deleted Process: P1 4 × (s.0)4=¤4(0)4(0)4(0)4¤ P2 4 × (s.1)4=¤3(1)2(1)2(1)3¤ image P3 4 × (s.2)4=¤2(6)2¤ P4 4 × (s.3)4=¤1(5)1¤ P5 4 × (s.4)4=0 General form a × (s.0)b=c a × (s.1)b=c ... a × (c.d)b=c [s29]-multiplication subtraction CM-[s29]-does no know ×You will see a sign in the PDF Link to comment Share on other sites More sharing options...
badeskov Posted February 6, 2012 #50 Share Posted February 6, 2012 As this being a discussion forum and all, any chance that you at some point want to discuss your "math", or are you satisfied with just posting your math manifesto and subsequently ignore all feedback? I am guessing the reason that you are posting here and not in some math forum or (oh, the horror) for peer review is the glaring issues with what you are trying to do. Why not take that critical feedback and use it instead of ignoring it? Frankly, looking at your attitude so far you'd never get through peer review. Cheers, Badeskov Link to comment Share on other sites More sharing options...
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