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srdanova math

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Mr. msbiljanica, start you can english wayno understand thou?

Seriously, try a little bit harder to express your thoughts in the way everyone could understand. And what a hell is srcko? Cheese in circus?

And, BTW, will your "new math" help me solve system of differential equations easier than "old math"?

Edit: grammar

Edited by bmk1245

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Just because some find to be easier to understand and demonstrate than others, that doesn't make it child's play. I am sure that Stephen Hawking would find calculus to be child's play...

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Mr. msbiljanica, start you can english wayno understand thou?

Seriously, try a little bit harder to express your thoughts in the way everyone could understand. And what a hell is srcko? Cheese in circus?

And, BTW, will your "new math" help me solve system of differential equations easier than "old math"?

Edit: grammar

srcko ab, abc , 55={5,10,15,20,...} ,22222={2,4,6,...,220,222}

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bmk1245, on 27 January 2012 - 11:14 PM, said:

application modeler forum - because I had problems with an Internet connection, to delete the previous post (to leave only one)

_________________________________________________

Presupposition-Two ( more ) srcko have the first ( last) common number

Process:

P1 10530 and 3330 , 10533(_30)

P2 4444 and 441094 and 44256 , 44(_44_)1094256

...

General form -abcd(_e) , ab(_c_)defg , ...

[s17]-two ( more) first-last srcko

CM-[s17]-does no know

______________________________________________________

Presupposition-In the expression a+(.b)c=d , d+(s.0)11 or d+(s.0)number (more) from 11

Process:

P1 3+(.s.0)5=8+(s.0)11 , 3+(s.0)5<91

P2 5+(.0)5=5+(s.0)224 , 5+(.0)5<729

...

General form - a+(.b)c=d+(s.0)11 ,a+(s.b)c<e1

a+(.b)c=d+(s.0)e , a+(.b)c<f

a+(.b)c=d+(s.0)efg , a+(.b)c<hij ...

[s18]-left inequality

CM-[s18]-know

_______________________________________

2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,

2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,

2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94

srcko

5550={5,10,15,20,25,30,35,40,45,50}

38350={38,41,44,47,50}

501090={50,60,70,80,90}

50792={50,57,64,71,78,85,92}

two(more) first-last srcko

55383(_50_)1090792

remains part of the function, when we come to it

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Just because some find to be easier to understand and demonstrate than others, that doesn't make it child's play. I am sure that Stephen Hawking would find calculus to be child's play...

Well, if Stephen Hawking would rename differential operator (d/dx) into coombacoombla and call it new math, that would be child's play. I can come up with dozen symbols for sum operator, that wouldn't make my math new, nor any better.

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srcko ab, abc , 55={5,10,15,20,...} ,22222={2,4,6,...,220,222}

Thanks, I guess...

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Uhm, ok.

So what does N2M mean in your math? I am guessing N2M={N, N+2, N+4,...,M}. If correct, great, so now you have redefined how we denote sets. So, how do you now denote variables? Like the variables N1, N2, M19 etc?

Cheers,

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Thanks, I guess...

I rather like it. You know, bmk, d/dx is rather boring and dull. Also, coombacoombla is a nice long and good sounding word, it sooo takes the emphasis over boring numbers in long equations

Cheers,

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I rather like it. You know, bmk, d/dx is rather boring and dull. Also, coombacoombla is a nice long and good sounding word, it sooo takes the emphasis over boring numbers in long equations

Cheers,

Math (as well as other scientific) books would be unliftable

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Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete

Process:

P1 4-(.0)2=2

P2 4-(.1)2=¤1(2)1¤ image

P3 4-(.2)2=2

P4 4-(.3)2=¤3(1)1¤

P5 4-(.4)2=¤4(0)2¤

General form

a-(.0)b=c

a-(.1)b=c

...

a-(.d)b=c

[s19]-subtraction

CM-only form a-(s.0/s.0)b=c , others do not know , axiom

_______________________________________________________________________

Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f

Process:

P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017

P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321

...

General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e

a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f

a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...

CM-[s20]-know

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Sooo, care to elaborate on how you denote variables in your math?

Cheers,

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Presupposition-Two ( more) addition (left and right inequalities) can be short to write

Process:

P1 3+(.013)4=y , 3+(.013)4>y ,3+(.013)4<y

P2 8+(.228)5=y , 8+(.228)5>y ,8+(.228)5<y

...

General form - a+(.bcd)e=y ,a+(.bcd)e>y , a+(.bcd)e<y

a+(.bcd_e)f=y , a+(.bcd_e)f>y , a+(.bcd_e)f<y ,...

CM-[s21]-does no know

______________________________________________________

Presupposition-Gap number ( value z) is a variable (same value) with the gaps that is constant

Process:

P1 ¤5(2)0¤,¤4(2)1¤,3(2)2¤,¤2(2)3¤,¤1(2)4¤,¤0(2)5¤ --5¤¤(2)

P2 ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤

¤2(2)0¤,¤1(2)1¤.¤0(2)2¤

¤1(2)0¤,¤0(2)1¤

¤0(2)0¤ --013¤¤(2)

¤2(2)0¤,¤1(2)1¤,¤0(2)2¤

¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤

...

21¤¤(2)

[s22]-variability of z number

CM-[s22]-does no know

_______________________________________-

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Sooo, care to elaborate on how you denote variables in your math?

I guess that is a no then....

Cheers,

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I guess that is a no then....

Yeah, it seems like msbiljanica is just dumping his ``mathematics manifesto'' into google translate and then throwing it up on the forums, rather than actively explaining or discussing the content of his posts.

I mean since the OP stated that current mathematics were ``limited and sinful'' (emphasis mine) - which I am assuming (or hoping!) was just a poor translation - I wouldn't hold my breath for any extra insight into his existing posts.

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Yeah, it seems like msbiljanica is just dumping his ``mathematics manifesto'' into google translate and then throwing it up on the forums, rather than actively explaining or discussing the content of his posts.

I mean since the OP stated that current mathematics were ``limited and sinful'' (emphasis mine) - which I am assuming (or hoping!) was just a poor translation - I wouldn't hold my breath for any extra insight into his existing posts.

I fear that you are correct in your assessment - not unexpectedly, though. And I wonder too how current mathematics are sinful. I have heard mathematics being called much, but I think sinful is a first.

Cheers,

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Presupposition-Translation of gap number in the variability z ( with constant gap ) can addition

(s.0)

Process:

P1 ¤3(2)3¤+(.z)¤4(2)4=6¤¤(2)+(.z)8¤¤(2)=14¤¤(2)

P2 ¤1(6)1(9)1¤+(.z)¤3(6)2(9)1¤=3¤¤(6)(9)+(.z)6¤¤(6)(9)=9¤¤(6)(9)

...

General form ¤a(b)c¤+(.z)¤d(b)e¤=f¤¤(b )+(.z)g¤¤(b )=h¤¤(b ) ...

CM-[s23]-does no know

__________________________________________

Presupposition-Translation of gap number in the variability z ( with constant gap ) can subtraction

(s.0/s.0)

Process:

P1 ¤3(2)3¤-(.z)¤1(2)1=6¤¤(2)-(.z)2¤¤(2)=4¤¤(2)

P2 ¤3(6)2(9)1¤-(.z)¤1(6)1(9)1¤=6¤¤(6)(9)-(.z)3¤¤(6)(9)=3¤¤(6)(9)

...

General form ¤a(b)c¤-(.z)¤d(b)e¤=f¤¤(b )-(.z)g¤¤(b )=h¤¤(b ) ...

[s24]-z subtraction

CM-[s24]-does no know

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Presupposition-In the expression a-(.b)c=d , d+(s.0))11 or d+(s.0)number (more) from 11

and d+(.z)11¤¤e or d+(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...}

Process:

P1 4-(.2)2=2+(s.0)11 , 4-(.2)2<31

4-(.3)2=¤1(2)1¤+(.z)11¤¤(2) , 4-(.3)2<2¤¤(2)+(.z)11¤¤(2) , 4-(.3)2<31¤¤(2)

P2 4-(.2)2=2+(s.0)4 , 4-(.2)2<6

4-(.3)2=¤1(2)1¤+(.z)7¤¤(2) , 4-(.3)2<2¤¤(2)+(.z)7¤¤(2), 4-(.3)<9¤¤(2)

...

General form - a-(.b)c=d-(s.0)11 ,a+(s.b)c<g1

a-(.b)c=d+(s.0)g , a+(.b)c<l

a-(.b)c=d+(s.0)kpg , a+(.b)c<hij ...

a-(.b)c=d+(.z)11¤¤e , a-(.b)c<s¤¤e+(.z)11¤¤e , a+(s.b)c<g1¤¤e

a-(.b)c=d+(.z)g¤¤e , a-(.b)c<s¤¤¤e+(.z)g¤¤e , a+(.b)c<l¤¤e

a-(.b)c=d+(.z)kpg¤¤e , a-(.b)c<s¤¤e+(.z)kpg¤¤e , a+(.b)c<hij¤¤e ...

[s25]-left inequality subtraction

CM-[s25]-know , forms without any gaps numbers not known

____________________________________________________________________

Presupposition-In the expression a-(.b)c=d , d-(s.0/s.0))11p or d+(s.0/s.0)number (more) from 11p

and d-(.z)11p¤¤e or d-(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...}

Process:

P1 4-(.2)2=2-(s.0/s.0))112 , 4-(.2)2>011

4-(.3)2=¤1(2)1¤-(.z)211¤¤(2) , 4-(.3)2>2¤¤(2)-(.z)211¤¤(2) , 4-(.3)2>011¤¤(2)

P2 4-(.2)2=2-(s.0/s.0))1 , 4-(.2)2>1

4-(.3)2=¤1(2)1¤-(.z)1¤¤(2) , 4-(.3)2>2¤¤(2)-(.z)1¤¤(2) , 4-(.3)>1¤¤(2)

...

General form - a-(.b)c=d-(s.0/s.0)11p ,a-(s.b)c>g1l

a-(.b)c=d-(s.0/s.0))g , a-(.b)c>l

a-(.b)c=d-(s.0/s.0))ksg , a-(.b)c>hij ...

a-(.b)c=d-(.z)11p¤¤e , a-(.b)c>s¤¤e-(.z)11p¤¤e , a-(s.b)c>g1k¤¤e

a-(.b)c=d-(.z)g¤¤e , a-(.b)c>s¤¤e-(.z)g¤¤e , a-(.b)c>l¤¤e

a-(.b)c=d-(.z)kpg¤¤e , a-(.b)c>s¤¤e-(.z)kpg¤¤e , a-(.b)c>hij¤¤e ...

[s26]-right inequality subtraction

CM-[s26]-know , forms without any gaps numbers not known

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Presupposition-Two ( more) subtraction (left and right inequalities) can be short to write

Process:

P1 7-(.013)4=y , 7-(.013)4>y ,7-(.013)4<y

P2 8-(.228)5=y , 8-(.228)5>y ,8-(.228)5<y

...

General form a-(.bcd)e=y ,a-(.bcd)e>y , a-(.bcd)e<y

a-(.bcd_e)f=y , a-(.bcd_e)f>y , a-(.bcd_e)f<y ,...

[s27]-function subtraction

CM-[s27]-does no know

_____________________________________

Presupposition-Parts number (a) and mobile number (b ) have a contact , contact remains , the

rest is delete

Process:

P1 4 - (.0)2=2

P2 4 - (.1)2=2 image

P3 4 - (.2)2=2

P4 4 - (.3)2=1

P5 4 - (.4)2=1

General form

a - (.0)b=c

a - (.1)b=c

...

a - (.d)b=c

[s28]-opposite subtraction

CM-[s28]-does no know

-sign for. opposite subtraction (when you download the following PDF you will see how it looks)

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3.how to solve this current knowledge of mathematics:

along a (20m) ,deleted between 10 m and 15 m (b=5m) , wet get c

20m-(.5m)=¤10m(5m)5m¤

___________________________________________________

Presupposition-In the expression a - (.b)c=d , d+(s.0))11 or d+(s.0)number (more) from 11

and d+(.z)11¤¤e or d+(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...}

Process:

P1 5 - (.0)5=5+(s.0)11 , 5 - (.0)5<61

¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤+(.z)11¤¤(2)

¤2(2)2¤ - (.1)¤1(1)2¤<2¤¤(2)+(.z)11¤¤(2) , ¤2(2)2¤ - (.1)¤1/1)2¤<31¤¤(2)

P2 5 - (.0)5=5+(s.0)4 , 5 - (.0)5<9

¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤+(.z)7¤¤(2)

¤2(2)2¤ - (.1)¤1(1)2)¤<2¤¤(2)+(.z)7¤¤(2), ¤2(2)2¤ - (.1)¤1(1)2¤<9¤¤(2)

...

General form a - (.b)c=d-(s.0)11 ,a - (s.b)c<g1

a - (.b)c=d+(s.0)g , a - (.b)c<l

a - (.b)c=d+(s.0)kpg , a - (.b)c<hij ...

a -(.b)c=d+(.z)11¤¤e , a - (.b)c<s¤¤e+(.z)11¤¤e , a - (s.b)c<g1¤¤e

a - (.b)c=d+(.z)g¤¤e , a - (.b)c<s¤¤¤e+(.z)g¤¤e , a - (.b)c<l¤¤e

a - (.b)c=d+(.z)kpg¤¤e , a - (.b)c<s¤¤e+(.z)kpg¤¤e , a - (.b)c<hij¤¤e ...

[s29]-left inequality opposite subtraction

CM-[s29]-does no know

_________________________________

Presupposition-In the expression a - (.b)c=d , d-(s.0/s.0))11p or d+(s.0/s.0)number (more) from

11p and d-(.z)11p¤¤e or d-(.z) number ( more ) from 11¤¤e , e={(f),(f)(f),(f)(f)(f),...}

Process:

P1 5 - (.0)5=5 -(s.0/s.0))115 , 5 - (.0)5>014

¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤-(.z)211¤¤(2)

¤2(2)2¤ - (.1)¤1(1)2¤>2¤¤(2)-(.z)211¤¤(2) , ¤2(2)2¤ - (.1)¤1(1)2¤>011¤¤(2)

P2 5 - (.0)5=5-(s.0/s.0))1 , 5 - (.0)5>1

¤2(2)2¤ - (.1)¤1(1)2¤=¤1(2)1¤-(.z)1¤¤(2)

¤2(2)2¤ - (.1)¤1(1)2¤>2¤¤(2)-(.z)1¤¤(2) , ¤2(2)2¤ - (.1)¤1(1)2¤>1¤¤(2)

...

General form a - (.b)c=d-(s.0/s.0)11p ,a - (s.b)c>g1l

a - (.b)c=d-(s.0/s.0))g , a - (.b)c>l

a - (.b)c=d-(s.0/s.0))ksg , a - (.b)c>hij ...

a - (.b)c=d-(.z)11p¤¤e , a - (.b)c>s¤¤e-(.z)11p¤¤e , a - (s.b)c>g1k¤¤e

a - (.b)c=d-(.z)g¤¤e , a - (.b)c>s¤¤e-(.z)g¤¤e , a - (.b)c>l¤¤e

a - (.b)c=d-(.z)kpg¤¤e , a - (.b)c>s¤¤e-(.z)kpg¤¤e , a - (.b)c>hij¤¤e ...

[s30]-right inequality opposite subtraction

CM-[s30]-does no know

__________________________________-

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Presupposition-Two ( more) opposite subtraction (left and right inequalities) can be short to write

Process:

P1 7 - (.013)4=y , 7 - (.013)4>y ,7 - (.013)4<y

P2 8 - (.228)5=y , 8 - (.228)5>y ,8 - (.228)5<y

...

General form a - (.bcd)e=y ,a - (.bcd)e>y , a - (.bcd)e<y

a - (.bcd_e)f=y , a - (.bcd_e)f>y , a - (.bcd_e)f<y ,...

[s31]-function opposite subtraction

CM-[s31]-does no know

__________________________________

Presupposition-Two ( more) addition the same number can be written in shorted form

Process:

P1 a+(s.c)a=a×(s.c)2 , a×(s.c)b

P2 a+(s.c)a+(s.c)a=a×(s.c)3 , a×(s.c)b

P3 a+(s.c)a+(s.c)a+(s.c)a=a×(s.c)4 , a×(s.c)b

...

[s32]-multiplication

CM-[s32]-know , axiom

Presupposition-In terms a×(s.c)b , b can be number 0 (1)

Process:

P1 a×(s.c)0

P2 a×(s.c)1

[s32a]-multiplication-amendment

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<snipped uninteresting stuff>

Seriously, why don't you get a blog? You obviously have no interest in discussing your so called "new math", which makes it rather uninteresting for a discussion forum - not that this "new math" contributes anything anyways. You can't even tell me how you denote variables with indices, which is a rather large flaw.

Good grief.

Cheers,

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Presupposition-In terms a×(s.c)b , multiplication

Process:

P1 4×(s.0)4=16

P2 4×(s.1)4=13 image

P3 4×(s.2)4=10

P4 4×(s.3)4=7

P5 4×(s.4)4=4

P1 ¤1(2)1¤×(s.0)4=¤1(2)2(2)2(2)2(2)1¤

P2 ¤1(2)1¤×(s.1)4=¤1(2)1(2)1(2)1(2)1¤ image

P3 ¤1(2)1¤×(s.2)4=¤1(1)6(1)1¤

P4 ¤1(2)1¤×(s.3)4=7

P5 ¤1(2)1¤×(s.4)4=¤1(2)1¤

General form

a×(s.0)b=c

a×(s.1)b=c

...

a×(c.d)b=c

[s32b]-multiplication

CM-[s32b]-know a×(s.0)b other do not know , forms withuut any gaps numbers not known

Sigh.....

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___________________________________________

Presupposition-The numbers are multiplication , where a contact is deleted

Process:

P1 4 × (s.0)4=¤4(0)4(0)4(0)4¤

P2 4 × (s.1)4=¤3(1)2(1)2(1)3¤ image

P3 4 × (s.2)4=¤2(6)2¤

P4 4 × (s.3)4=¤1(5)1¤

P5 4 × (s.4)4=0

General form

a × (s.0)b=c

a × (s.1)b=c

...

a × (c.d)b=c

[s29]-multiplication subtraction

CM-[s29]-does no know

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As this being a discussion forum and all, any chance that you at some point want to discuss your "math", or are you satisfied with just posting your math manifesto and subsequently ignore all feedback? I am guessing the reason that you are posting here and not in some math forum or (oh, the horror) for peer review is the glaring issues with what you are trying to do. Why not take that critical feedback and use it instead of ignoring it?

Frankly, looking at your attitude so far you'd never get through peer review.

Cheers,