Ozymandias Posted April 11, 2019 #301 Share Posted April 11, 2019 6 hours ago, Harte said: The disc centers form a 3-4-5 triangle. The right angle in that triangle sweeps out a fourth of the 1 meter circle area. The other two angles are not as clean (apprx. 53.13 degrees and it's complement.) The area of the triangle is 6. The sum of the areas areas of the sectors of the discs is approximately 5.59. The difference is 0.41 m2 . That's with rounding. I didn't feel like putting in the time to express it in terms of pi. Left my good calculator in my classroom. That's a nice problem and I'm certain there are several other ways to solve it. Harte That was quick, Harte. I bet you enjoyed that! Whatever about other solution methods your method is the way I had envisaged solving it. Your result, 0.41m^2, is correct but without your calculator it is not very accurate. A more precise answer is 0.4643m^2 to the nearest cm^2. Looking forward to your problem. 1 Top Link to comment Share on other sites More sharing options...
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