Ozymandias Posted October 3, 2020 #426 Share Posted October 3, 2020 On 10/1/2020 at 6:55 PM, Ozymandias said: Since nobody is bothering to upload another teaser and I have one of my own to hand .............. Problem: a triangle ABC has sides 7m, 8m and 9m in length. Its area is 26.833m^2. What is the radius of its incircle? I'll give the answer to this problem tomorrow as nobody seems interested and. like the last time, we can let this thread die a death. Link to comment Share on other sites More sharing options...
Ozymandias Posted October 4, 2020 #427 Share Posted October 4, 2020 (edited) On 10/3/2020 at 12:12 PM, Ozymandias said: I'll give the answer to this problem tomorrow as nobody seems interested and. like the last time, we can let this thread die a death. Problem: a triangle ABC has sides 7m, 8m and 9m in length. Its area is 26.833m^2. What is the radius of its incircle? Solution: The area of the triangle ABC is 26.833m^2 and is made up of the area of the triangle ABO, ACO and BCO. Each of these three triangles have a base equal to one of the sides of ABC and a perpendicular height, r, equal to the radius of the incircle. Area ABC = area ABO + area ACO + area BCO 26.833m^2 = 1/2(8)(r) + 1/2(9)(r) + 1/2(7)(r) 26.833m^2 = 1/2(r)(8 + 9 + 7) r = 26.833/[1/2(24)] = 2.236m to the nearest millimetre Edited October 4, 2020 by Ozymandias 1 1 Link to comment Share on other sites More sharing options...
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